「javaurlen」javaurlencode转码怎么忽略安全码

博主:adminadmin 2023-03-17 01:45:05 589

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本文目录一览:

java url 编码

POST过去的数据是不用URL编码的。

你先request.getParameter("xm")获取下,看是否正确,如果是问号的话就转换下

new String(request.getParameter("xm").getBytes("iso8859_1"),"gbk");

你这个是在Java里面获取的?request是JSP里面的一个对象,在Java里就需要传入一个HttpServletRequest实例了。

java怎么提取下面字符串中的地址

这个可以用正则表达式,给你写了个简单的你代码,我测试过了,希望对你有帮助~!

import java.util.regex.Matcher;

import java.util.regex.Pattern;

public class ExtractAddress {

public static void main(String[] args) {

String s = "var _url = \"\";";

Pattern pattern = Pattern.compile("\"(.*)\"");

Matcher m = pattern.matcher(s);

if(m.find())

System.out.println(m.group(1));

else

System.out.println("没找到相关地址");

}

}

java 用 HttpClients 请求 url 返回状态码是 503 怎么处理

// 用getResponseCode可以获取a href=";tn=44039180_cprfenlei=mv6quAkxTZn0IZRqIHckPjm4nH00T1d9rHnkmWD3nWbdnANBnj-W0ZwV5Hcvrjm3rH6sPfKWUMw85HfYnjn4nH6sgvPsT6KdThsqpZwYTjCEQLGCpyw9Uz4Bmy-bIi4WUvYETgN-TLwGUv3EnHRYnHndP1fdPH6Ynj0snWfzPs" target="_blank" class="baidu-highlight"URL/a返回状态码

String sa href=";tn=44039180_cprfenlei=mv6quAkxTZn0IZRqIHckPjm4nH00T1d9rHnkmWD3nWbdnANBnj-W0ZwV5Hcvrjm3rH6sPfKWUMw85HfYnjn4nH6sgvPsT6KdThsqpZwYTjCEQLGCpyw9Uz4Bmy-bIi4WUvYETgN-TLwGUv3EnHRYnHndP1fdPH6Ynj0snWfzPs" target="_blank" class="baidu-highlight"url/a = "";

try {

sa href=";tn=44039180_cprfenlei=mv6quAkxTZn0IZRqIHckPjm4nH00T1d9rHnkmWD3nWbdnANBnj-W0ZwV5Hcvrjm3rH6sPfKWUMw85HfYnjn4nH6sgvPsT6KdThsqpZwYTjCEQLGCpyw9Uz4Bmy-bIi4WUvYETgN-TLwGUv3EnHRYnHndP1fdPH6Ynj0snWfzPs" target="_blank" class="baidu-highlight"url/a="你的url";

URL url = new URL(surl);

URLConnection rulConnection = url.openConnection();

HttpURLConnection httpUrlConnection = (HttpURLConnection) rulConnection;

httpUrlConnection.setConnectTimeout(300000);

httpUrlConnection.setReadTimeout(300000);

httpUrlConnection.connect();

String code = new Integer(httpUrlConnection.getResponseCode()).toString();

String message = httpUrlConnection.getResponseMessage();

System.out.println("getResponseCode code ="+ code);

System.out.println("getResponseMessage message ="+ message);

if(!code.startsWith("2")){

throw new Exception("ResponseCode is not begin with 2,code="+code);

}

System.out.println(getCurDateTime()+"连接"+surl+"正常");

}catch(Exception ex){

System.out.println(ex.getMessage());

}

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