「java数组倒序排列」java数组倒序输出
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java array倒序
java中有方法直接实现array的倒叙的。可以用Collections的reverse方法即可:
ArrayList al = new ArrayList();
al.add("a");
al.add("b");
//al.add("b");
Collections.reverse(al);
System.out.println(al);
输出结果:[b, a]。
java中怎么将一个字符数组反序
可以用Collection.reverse(list)呀,先把你的数组放到List里,再Collection.reverse(list),然后再从list中拿回来,示例代码:
public
static
void
main(String[]
args)
{
String[]
deal
=
new
String[3];
deal[0]
=
"0";
deal[1]
=
"1";
deal[2]
=
"2";
ListString
list
=
new
ArrayListString();
for
(int
i
=
0;
i
deal.length;
i++)
{
list.add(i,
deal[i]);
}
Collections.reverse(list);
for
(int
i
=
0;
i
list.size();
i++)
{
deal[i]
=
list.get(i);
}
for
(int
i
=
0;
i
deal.length;
i++)
{
System.out.println(deal[i]);
}
}
Java 数组倒序输出?
1、逆序数组有很多种方法,比如先排序,再逆序存
public static void main(String[] args) {
int[] nums = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19};
System.out.print("原数组:");
for (int num : nums) {
System.out.print(num+" ");
}
System.out.print("\n倒序新数组:");
for (int num : reverseArray1(nums)) {
System.out.print(num + " ");
}
}
//1.排序后倒序
public static int[] reverseArray1(int[] nums) {
Arrays.sort(nums);
int[] reNums = new int[nums.length];
for (int i = 0; i nums.length; i++) {
reNums[i] = nums[nums.length - 1 - i];
}
return reNums;
}
//2.Collection 内置的逆序
public static int[] reverseArray2(int[] nums) {
ArrayListInteger list = new ArrayList();
for (int i = 0; i nums.length; i++) {
list.add(nums[i]);
}
Collections.reverse(list);
int [] reNums = new int[nums.length];
for (int i = 0; i nums.length ; i++) {
reNums[i] = list.get(i);
}
return reNums;
}
java 数组进行倒序排序
这个简单
String s[] = {1,2,3,4,5,6,7};
for (int i = 0; i s.length; i ++){
System.out.print(s[s.length-1-i] +",");
}
JAVA String类型的数组怎么逆序排序
String[] a = new String[]{"A","B","C","D","E"};
String[] b=new String[a.length];
int indexA=a.length-1,indexB=0;
for(String s:a){
b[indexB]=a[indexA];
indexA--;
indexB++;
}
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