「用java遍历xml」java集合的遍历

本篇文章给大家谈谈用java遍历xml，以及java集合的遍历对应的知识点，希望对各位有所帮助，不要忘了收藏本站喔。

本文目录一览：

• 1、如何用java遍历出xml中每一个attributeValue的值
• 2、java 如何遍历xml并输出每个节点的每个属性？
• 3、Java xml遍历
• 4、求大虾help! 如何用java遍历n个xml文件,并取得xml文件的各个属性..如果有代码的话就更好了.跪谢~

如何用java遍历出xml中每一个attributeValue的值

递归读取法即可

package tool;

import java.util.Scanner;

import javax.xml.parsers.DocumentBuilder;

import javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.Document;

import org.w3c.dom.NamedNodeMap;

import org.w3c.dom.Node;

import org.w3c.dom.NodeList;

public class XMLTool

{

private static final String XML = "MyXml.xml";

private static Document getDoc ( String xml )

{

DocumentBuilderFactory dbf = null;

DocumentBuilder db = null;

Document doc = null;

try

{

dbf = DocumentBuilderFactory.newInstance ();

db = dbf.newDocumentBuilder ();

doc = null == xml ? db.newDocument () : db.parse (xml);

return doc;

}

catch (Exception e)

{

e.printStackTrace ();

}

return null;

}

private static void readXML ( String xml, String... looks )

{

Document doc = getDoc (xml);

recursionXML (doc, looks);

}

private static void recursionXML ( Node node, String... looks )

{

NodeList nl = node.getChildNodes ();

if (nl.getLength () == 0)

{

return;

}

for ( int i = 0; i nl.getLength (); i++ )

{

Node n = nl.item (i);

Node parentNode = n.getParentNode ();

NamedNodeMap nnm = parentNode.getAttributes ();

if (

looks.length != 0

parentNode.getNodeName ().equals (looks[0])

nnm.getNamedItem (looks[1]).getNodeValue ().equals (looks[2])

)

{

System.out.println (nnm.getNamedItem ("Status"));

}

recursionXML (n, looks);

}

}

public static void main ( String[] args )

{

System.out.println ("输入id号进行查询: (n/N 退出)");

Scanner scanner = new Scanner (System.in);

String[] looks = { "UseTicketResult", "TicketNo", "47" };

String line = null;

while (scanner.hasNextLine ())

{

line = scanner.nextLine ().trim ();

if ("n".equalsIgnoreCase (line))

{

scanner.close ();

break;

}

looks[2] = line;

readXML (XML, looks);

System.out.println ("继续输入: ");

}

}

}

java 如何遍历xml并输出每个节点的每个属性？

//打印xml文档

private void parseElement(Element root)

{

//System.out.print(root.getNamespaceURI());

System.out.print("");

System.out.print(root.getNodeName());

//System.out.print(root.getPrefix());

//System.out.print(":");

//System.out.print(root.getLocalName());

NamedNodeMap nnm = root.getAttributes();

for(int i = 0; i nnm.getLength(); i++)

{

Attr attr = (Attr)nnm.item(i);

System.out.print(" ");

System.out.print(attr.getName());

System.out.print("=\"");

System.out.print(attr.getValue());

System.out.print("\"");

}

System.out.print("");

NodeList list = root.getChildNodes();

for(int i = 0; i list.getLength(); i++)

{

Node node = list.item(i);

if(node instanceof Element)

{

Element e = (Element)node;

parseElement(e);

}

else if(node instanceof Text)

{

Text t = (Text)node;

System.out.print(t.getNodeValue());

}

}

System.out.print("/");

System.out.print(root.getNodeName());

System.out.print("");

}

private void parseRootName()

{

Element root = doc.getDocumentElement();

System.out.println(root.getNodeName());

}

//工厂

private void getDocument()

{

try

{

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

factory.setNamespaceAware(true);

DocumentBuilder db = factory.newDocumentBuilder();

doc = db.parse(new File(fileName));

}

catch(Exception ex)

{

ex.printStackTrace();

System.exit(1);

}

}

Java xml遍历

你没说清楚运行是到底会发生什么错误，因为解析XML这玩意和XML本身的格式有关，你应该把XML也给出。我只能假设你的XML是这种形式：

?xml version="1.0" encoding="UTF-8" ?

root

    filems name="a1" Englishname="a2" direct="a3" actor="a4" type="a5"

        price="a6" time="a7" /

    filems name="b1" Englishname="b2" direct="b3" actor="b4" type="b5"

        price="b6" time="b7" /

/root

这样运行你的代码会报NulPointerExceptoin，应该把Element e = (Element)  list.item(i).getChildNodes().item(i);

去掉，你的代码需要改成这样子：

import java.util.ArrayList;

import java.util.List;

import javax.xml.parsers.DocumentBuilder;

import javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.Document;

import org.w3c.dom.Element;

import org.w3c.dom.NodeList;

public class Filem {

    public static void main(final String[] args) throws Exception {

        show();

    }

    public static void show() throws Exception {

        final DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();

        final DocumentBuilder db = dbf.newDocumentBuilder();

        final Document doc = db.parse("FilemMessage.xml");

        final NodeList list = doc.getElementsByTagName("filems");

        final List l = new ArrayList();

        final int length = list.getLength();

        for (int i = 0; i  length; i++) {

            final Element e = (Element) list.item(i);

            if (e == null) {

                break;

            }

            final String name = e.getAttribute("name");

            final String Englishname = e.getAttribute("Englishname");

            final String direct = e.getAttribute("direct");

            final String actor = e.getAttribute("actor");

            final String type = e.getAttribute("type");

            final String price = e.getAttribute("price");

            final String time = e.getAttribute("time");

            l.add(name);

            l.add(Englishname);

            l.add(direct);

            l.add(actor);

            l.add(type);

            l.add(price);

            l.add(time);

        }

        for (int j = 0; j  l.size(); j++) {

            System.out.println(l.get(j));

        }

    }

}

求大虾help! 如何用java遍历n个xml文件,并取得xml文件的各个属性..如果有代码的话就更好了.跪谢~

jdom解析xml

下面是xml文件:

?xml version="1.0" encoding="UTF-8"?

persons

person perid="1001"

namelhu/name

age89/age

address安徽淮北/address

sex男/sex

/person

person perid="1002"

namewe/name

age56/age

address北京海淀/address

sex女/sex

/person

/persons

下面是解析上面的xml文件:

通过JDOM来解析,需要借助第三方的组件.jdom.jar,网上有1.0的版本下载

package cn.com.jdom;

import java.io.File;

import java.io.IOException;

import java.util.Iterator;

import java.util.List;

import org.jdom.Attribute;

import org.jdom.Document;

import org.jdom.Element;

import org.jdom.JDOMException;

import org.jdom.ProcessingInstruction;

import org.jdom.input.SAXBuilder;

import com.sun.xml.internal.bind.v2.runtime.Name;

/**

* jdom解析xml文件

*

* @author ly *

*/

public class JDomXML {

public JDomXML() {

}

/**

* 解析xml文件

* @param xmlFile

*/

public void parseXml(File xmlFile) {

SAXBuilder sax = new SAXBuilder();//在内存中建立一个sax文档模型

try {

Document xmlDom = sax.build(xmlFile);//创建文档

//获得文件的根元素

Element root = xmlDom.getRootElement();

System.out.println("根元素是:"+root.getName());

//获得根元素的子节点

List childList = root.getChildren();

Iterator listIt = childList.iterator();

while(listIt.hasNext()){

Element element = (Element)listIt.next();

System.out.println("孩子结点是:"+element.getName());

}

//获得第一个孩子结点

Element firstChild = (Element) childList.get(0);

//获得孩子结点的属性

List attrList = firstChild.getAttributes();

Iterator attrIt = attrList.iterator();

while(attrIt.hasNext()){

Attribute attr = (Attribute ) attrIt.next();

System.out.println("第一个元素的属性是:"+attr.getName());

//获得属性的值

System.out.println("属性的值是:"+attr.getValue());

//获得属性的类型

System.out.println("属性的类型是:"+attr.getAttributeType());

}

List sonList = firstChild.getChildren();

Iterator sonIt = sonList.iterator();

while(sonIt.hasNext()){

Element temp = (Element)sonIt.next();

System.out.println("属性"+temp.getName()+"的值是:"+temp.getValue());

}

} catch (JDOMException e) {

e.printStackTrace();

} catch (IOException e) {

e.printStackTrace();

}

}

public static void main(String[] args) {

JDomXML test = new JDomXML();

test.parseXml(new File("persons.xml"));

}

}

用java遍历xml的介绍就聊到这里吧，感谢你花时间阅读本站内容，更多关于java集合的遍历、用java遍历xml的信息别忘了在本站进行查找喔。