「数据结构java实验」数据结构Java实验三

博主:adminadmin 2023-01-10 10:21:10 781

今天给各位分享数据结构java实验的知识,其中也会对数据结构Java实验三进行解释,如果能碰巧解决你现在面临的问题,别忘了关注本站,现在开始吧!

本文目录一览:

用java实现一个数据结构!

import java.io.IOException;

import java.util.Scanner;

public class LinkList {

private static Scanner san = new Scanner(System.in);

public static void main(String[] args) throws IOException {

List list = new List();

for (int i = 1; i = 10; i++) {

System.out.print("请输入第" + i + "个数: ");

list.add(san.nextInt());

list.print();

}

System.out.println("输入的数据如下: ");

list.print();

}

}

class node {

int data;

node next = this; // 指向自己

}

class List {

private node header = new node();

// 循环链表的尾部添加数据

public node add(int data) {

node current = new node();

node temp = header;

while (temp.next != header)

temp = temp.next;

current.data = data;

current.next = temp.next;

temp.next = current;

return current;

}

// 查询某个数字的位置 如果不在 返回-1;

public int search(int data) {

node temp = header;

int n = 0;

while (temp.next != header) {

temp = temp.next;

n++;

if (temp.data == data)

break;

}

if (temp.data == data)

return n;

else

return -1;

}

// 打印出整个链表

public void print() {

node temp = header;

while (temp.next != header) {

temp = temp.next;

System.out.print(temp.data + " ");

}

System.out.println();

}

// 插入数据

public node Insert(int pos, int data) {

node temp = header;

node current = new node();

for (int i = 0; i pos - 1; i++) {

if (temp.next != header) {

temp = temp.next;

} else

return null;

}

current.data = data;

if (temp.next != header) {

current.next = temp.next;

}

temp.next = current;

return current;

}

// 删除某个数据

public node del(int data) {

node temp = header;

node oldtemp = null;

node current = null;

while (temp.next != header) {

oldtemp = temp;

temp = temp.next;

if (temp.data == data) {

current = temp;

break;

}

}

if (current == header)

return null;

oldtemp.next = current.next;

return current;

}

}

数据结构(Java版)实验2:使用一个栈,将十进制转换成二进制、八进制或十六进制。

public static String baseConverter(int decNumber,int base){

String[] digits = new String[]{"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"};

String result = "";

StackInteger remStack = new StackInteger();

while(decNumber 0){

int rem = decNumber % base;

remStack.push(rem);

decNumber = decNumber/base;

}

while(!remStack.isEmpty()){

result = result+digits[remStack.pop()];

}

return result;

}

这个可以任意转换,记得采纳啊

数据结构在java里如何实现?

首先Java没有指针(为了安全和方便编程).

其次数据结构和指针无关,和语言也无关.

Java封装好了各种基本的数据结构 比如:

数组,队列,Stack,HashTable,HashSet,HaspMap等等

你说的顺序表 Java中你可以用:

ArrayList 这个类:

例子:

如果你自己想用Java裸写一个类似功能的类可以参考这个:

Java数据结构,程序报错

import java.util.LinkedList;

import java.util.Queue;

import java.util.Scanner;

public class SeqQueue {

public static void main(String[] args) {

QueueString sq = new LinkedListString();

while (true) {

System.out.println("请输数字:");

Scanner scan = new Scanner(System.in);

int i = scan.nextInt();

String s = String.valueOf(i);

if (i == 0) {

System.exit(0);

}

if (i % 2 == 1) {

sq.add(s);

} else {

sq.poll();

}

for (String ss : sq) {

System.out.println(ss);

}

}

}

}

求数据结构(JAVA版)实验树和二叉树题目答案

/**

* @param args

之前在大学的时候写的一个二叉树算法,运行应该没有问题,就看适不适合你的项目了 */

public static void main(String[] args) {

BiTree e = new BiTree(5);

BiTree g = new BiTree(7);

BiTree h = new BiTree(8);

BiTree l = new BiTree(12);

BiTree m = new BiTree(13);

BiTree n = new BiTree(14);

BiTree k = new BiTree(11, n, null);

BiTree j = new BiTree(10, l, m);

BiTree i = new BiTree(9, j, k);

BiTree d = new BiTree(4, null, g);

BiTree f = new BiTree(6, h, i);

BiTree b = new BiTree(2, d, e);

BiTree c = new BiTree(3, f, null);

BiTree tree = new BiTree(1, b, c);

System.out.println("递归前序遍历二叉树结果: ");

tree.preOrder(tree);

System.out.println();

System.out.println("非递归前序遍历二叉树结果: ");

tree.iterativePreOrder(tree);

System.out.println();

System.out.println("递归中序遍历二叉树的结果为:");

tree.inOrder(tree);

System.out.println();

System.out.println("非递归中序遍历二叉树的结果为:");

tree.iterativeInOrder(tree);

System.out.println();

System.out.println("递归后序遍历二叉树的结果为:");

tree.postOrder(tree);

System.out.println();

System.out.println("非递归后序遍历二叉树的结果为:");

tree.iterativePostOrder(tree);

System.out.println();

System.out.println("层次遍历二叉树结果: ");

tree.LayerOrder(tree);

System.out.println();

System.out.println("递归求二叉树中所有结点的和为:"+getSumByRecursion(tree));

System.out.println("非递归求二叉树中所有结点的和为:"+getSumByNoRecursion(tree));

System.out.println("二叉树中,每个节点所在的层数为:");

for (int p = 1; p = 14; p++)

System.out.println(p + "所在的层为:" + tree.level(p));

System.out.println("二叉树的高度为:" + height(tree));

System.out.println("二叉树中节点总数为:" + nodes(tree));

System.out.println("二叉树中叶子节点总数为:" + leaf(tree));

System.out.println("二叉树中父节点总数为:" + fatherNodes(tree));

System.out.println("二叉树中只拥有一个孩子的父节点数:" + oneChildFather(tree));

System.out.println("二叉树中只拥有左孩子的父节点总数:" + leftChildFather(tree));

System.out.println("二叉树中只拥有右孩子的父节点总数:" + rightChildFather(tree));

System.out.println("二叉树中同时拥有两个孩子的父节点个数为:" + doubleChildFather(tree));

System.out.println("--------------------------------------");

tree.exChange();

System.out.println("交换每个节点的左右孩子节点后......");

System.out.println("递归前序遍历二叉树结果: ");

tree.preOrder(tree);

System.out.println();

System.out.println("非递归前序遍历二叉树结果: ");

tree.iterativePreOrder(tree);

System.out.println();

System.out.println("递归中序遍历二叉树的结果为:");

tree.inOrder(tree);

System.out.println();

System.out.println("非递归中序遍历二叉树的结果为:");

tree.iterativeInOrder(tree);

System.out.println();

System.out.println("递归后序遍历二叉树的结果为:");

tree.postOrder(tree);

System.out.println();

System.out.println("非递归后序遍历二叉树的结果为:");

tree.iterativePostOrder(tree);

System.out.println();

System.out.println("层次遍历二叉树结果: ");

tree.LayerOrder(tree);

System.out.println();

System.out.println("递归求二叉树中所有结点的和为:"+getSumByRecursion(tree));

System.out.println("非递归求二叉树中所有结点的和为:"+getSumByNoRecursion(tree));

System.out.println("二叉树中,每个节点所在的层数为:");

for (int p = 1; p = 14; p++)

System.out.println(p + "所在的层为:" + tree.level(p));

System.out.println("二叉树的高度为:" + height(tree));

System.out.println("二叉树中节点总数为:" + nodes(tree));

System.out.println("二叉树中叶子节点总数为:" + leaf(tree));

System.out.println("二叉树中父节点总数为:" + fatherNodes(tree));

System.out.println("二叉树中只拥有一个孩子的父节点数:" + oneChildFather(tree));

System.out.println("二叉树中只拥有左孩子的父节点总数:" + leftChildFather(tree));

System.out.println("二叉树中只拥有右孩子的父节点总数:" + rightChildFather(tree));

System.out.println("二叉树中同时拥有两个孩子的父节点个数为:" + doubleChildFather(tree));

}

}

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