java中403的简单介绍
本篇文章给大家谈谈java中403,以及对应的知识点,希望对各位有所帮助,不要忘了收藏本站喔。
本文目录一览:
- 1、java项目发布到公网,post、get请求都返回403
- 2、java 抓取网站内容 异常Server returned HTTP response code: 403 ,求解
- 3、JAVa 如何返回HTTP status 403
- 4、java http 返回403 怎么解决?
java项目发布到公网,post、get请求都返回403
403表示forbidden服务器禁止你访问。一般是你的ip被对方服务器拉黑了。换个ip就没问题,公网ip。如果你在公司被禁止访问,换局域网ip没用,除非你公司的对外的公网ip更换。
java 抓取网站内容 异常Server returned HTTP response code: 403 ,求解
,不能从此网站中抓取内容;Windows );403命令是禁止恶意访问此网站;DigExt)" NT; .0;如果是服务器端禁止抓取, User-Agent".
connection;5;MSIE (compatible.0 Mozilla/4: ".setRequestProperty(",那么这个你可以通过设置User-Agent来欺骗服务器; HTTP ,提问者您好
JAVa 如何返回HTTP status 403
这是forbidden,缺少权限,一般是web验证没有通过会抛出的异常。
你可以在web.xml里面配置一些role,然后为role分配他的操作权限,你用用户登录的时候不给他分配操作权限的role,就会抛出403;
参考代码如下:
web.xml
security-constraint
web-resource-collection
web-resource-name测试403/web-resource-name
url-pattern/test/*/url-pattern
http-methodPOST/http-method
http-methodPUT/http-method
http-methodDELETE/http-method
/web-resource-collection
auth-constraint
role-nameadmin/role-name
/auth-constraint
user-data-constraint
transport-guaranteeNONE/transport-guarantee
/user-data-constraint
/security-constraint
!-- 用户登录验证方式 --
login-config
auth-methodBASIC/auth-method
/login-config
配置的tomcat服务器tomcat-user.xml
?xml version="1.0" encoding="UTF-8"?
!--
Licensed to the Apache Software Foundation (ASF) under one or more
contributor license agreements. See the NOTICE file distributed with
this work for additional information regarding copyright ownership.
The ASF licenses this file to You under the Apache License, Version 2.0
(the "License"); you may not use this file except in compliance with
the License. You may obtain a copy of the License at
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
--tomcat-users
!--
NOTE: By default, no user is included in the "manager-gui" role required
to operate the "/manager/html" web application. If you wish to use this app,
you must define such a user - the username and password are arbitrary.
--
!--
NOTE: The sample user and role entries below are wrapped in a comment
and thus are ignored when reading this file. Do not forget to remove
!.. .. that surrounds them.
--
!--
role rolename="tomcat"/
role rolename="role1"/
user username="tomcat" password="tomcat" roles="tomcat"/
user username="both" password="tomcat" roles="tomcat,role1"/
user username="role1" password="tomcat" roles="role1"/
--
role rolename="admin"/
role rolename="everyone"/
user username="testuser" password="testpwd" roles="everyone"/
/tomcat-users
java http 返回403 怎么解决?
1.先说下403的问题哈,你在程序中使用了url_con.getOutputStream().flush();
url_con.getOutputStream().close(); 这2个方法将会使得url_con释放与服务器的连接,此时,你后面的代码段想访问服务器的发回来输入流也已经被释放。当你把这2行代码注释掉就OK了。
2。text.concat(rd.readLine()); 这行代码应写成
text=text.concat(rd.readLine()); 原因:concat不修改text,只是返回text和参数连接后的字符串。
3。你还没有进行缓冲:应该每读一行或几行时把数据写出去(可以使用文件),不然程序执行缓慢甚至内存溢出。
4。你使用了rd.read()!=-1来判断流是否读完,但read每次使流的游标往前一次,因此你读到的文件每行都少一个字节(典型的就是少了行开头的),建议
String temp=null;
while(temp=rd.readLine())!=null){ text=text.concat(temp).concat("\n");
}
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发布于:2022-12-10,除非注明,否则均为
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